jose, paul and dan went fishing and all three of them caught a fish dan's fish weighed four times as much as paul,s fish and jose,s fish weigh half as much as dan,s fish altogether the three fish weighed 21 pounds. how much did each fish weigh?
Let x be Jose's weight
Let y be Paul's weight
Let z be Dan's weight
x + y + z = 21 (Equation #1)
z = 4*y, so y = z/4 (Equation #2)
x = (1/2)z = z/2 (Equation #3)
Replace (Equation #2) and (Equation #3) in (Equation #1)
z/2 + z/4 + z = 21
2z/4 + z/4 + 4z/4 = 21
7z/4 = 21
(4/7)* 7z/4 = 21 * 4/7
z = 84/7 = 12
x = z/2 = 12/2 = 6
y = z/4 = 12/4 = 3
Comments for Administrative assistant






Jun 08, 17 01:52 PM
Learn quickly how to multiply using partial products
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.
Jun 08, 17 01:52 PM
Learn quickly how to multiply using partial products