by Sana
(Islamabad,Pakistan.)
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is
the age of the youngest child?
Let x be the age of the youngest child.
Let x + 3 be the age of the second child.
Let x + 6 be the age of the third child.
Let x + 9 be the age of the fourth child.
Let x + 12 be the age of the fifth child.
The sum of their ages is equal to 50 as shown below
x + x + 3 + x + 6 + x + 9 + x + 12 = 50
x + x + x + x + x + 3 + 6 + 9 + 12 = 50
5x + 30 = 50
Subtract 30 from both sides
5x + 30 - 30 = 50 - 30
5x = 20
Divide both sides by 5
5x/5 = 20/5
x = 4
The age of the youngest child is 4.
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Oct 24, 16 06:10 PM
Straightforward proof of the law of sines. Easy to follow and understand