Sum of 3 consecutive odd integers is 3, what are the integers?
Solution
A number is odd if it has the following format: 2n + 1
Let 2n + 1 be the first odd integer
Let 2n + 3 be the second odd integer
Let 2n + 5 be the third odd integer
Since the sum is equal to 3, we get the following equation:
2n + 1 + 2n + 3 + 2n + 5 = 3
2n + 2n + 2n + 1 + 3 + 5 = 3
6n + 9 = 3
6n + 9  9 = 3  9
6n + 0 = 12
6n = 12
Divide both sides by 6
6n / 6 = 12 / 6
n = 2
The first odd integer is 2n + 1 = 2 × 2 + 1 = 4 + 1 = 3
The second odd integer is 2n + 3 = 2 × 2 + 3 = 4 + 3 = 1
The third odd integer is 2n + 5 = 2 × 2 + 5 = 4 + 5 = 1
The 3 consecutive odd integers are 3, 1, and 1
Indeed 3 + 1 + 1 = 3 + 0 = 3
Algebra ebook
Comments for Applications: Number problems and consecutive integers




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