Sum of 3 consecutive odd integers is 3, what are the integers?
Solution
A number is odd if it has the following format: 2n + 1
Let 2n + 1 be the first odd integer
Let 2n + 3 be the second odd integer
Let 2n + 5 be the third odd integer
Since the sum is equal to 3, we get the following equation:
2n + 1 + 2n + 3 + 2n + 5 = 3
2n + 2n + 2n + 1 + 3 + 5 = 3
6n + 9 = 3
6n + 9  9 = 3  9
6n + 0 = 12
6n = 12
Divide both sides by 6
6n / 6 = 12 / 6
n = 2
The first odd integer is 2n + 1 = 2 × 2 + 1 = 4 + 1 = 3
The second odd integer is 2n + 3 = 2 × 2 + 3 = 4 + 3 = 1
The third odd integer is 2n + 5 = 2 × 2 + 5 = 4 + 5 = 1
The 3 consecutive odd integers are 3, 1, and 1
Indeed 3 + 1 + 1 = 3 + 0 = 3
Algebra ebook
Comments for Applications: Number problems and consecutive integers




Jun 08, 17 01:52 PM
Learn quickly how to multiply using partial products
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.
Jun 08, 17 01:52 PM
Learn quickly how to multiply using partial products