2 m^{3} of soil containing 35% sand was mixed into 6 m^{3} of soil containing 15% sand. What is the sand content of the mixture?
Let x% be the amount of sand in the mixture
2 × 35% + 6 × 15% = (2 + 6) × x%
2 × 0.35 + 6 × 0.15 = 8 × x/100
0.7 + 0.9 = 8x / 100
1.6 = (8/100)x
1.6 = 0.08x
1.6/0.08 = x
x = 20
Therefore, there are 20% of soil in the mixture.
Sep 11, 17 05:06 PM
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