jose, paul and dan went fishing and all three of them caught a fish dan's fish weighed four times as much as paul,s fish and jose,s fish weigh half as much as dan,s fish altogether the three fish weighed 21 pounds. how much did each fish weigh?
Let x be Jose's weight
Let y be Paul's weight
Let z be Dan's weight
x + y + z = 21 (Equation #1)
z = 4*y, so y = z/4 (Equation #2)
x = (1/2)z = z/2 (Equation #3)
Replace (Equation #2) and (Equation #3) in (Equation #1)
z/2 + z/4 + z = 21
2z/4 + z/4 + 4z/4 = 21
7z/4 = 21
(4/7)* 7z/4 = 21 * 4/7
z = 84/7 = 12
x = z/2 = 12/2 = 6
y = z/4 = 12/4 = 3
Comments for Administrative assistant






Nov 15, 18 05:01 PM
Modeling multiplication with number counters  Learning multiplication is fun!
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.
Nov 15, 18 05:01 PM
Modeling multiplication with number counters  Learning multiplication is fun!
Our Top Pages
Formula for percentage
Compatible numbers
Basic math test
Basic math formulas
Types of angles
Math problem solver
Algebra word problems
Surface area of a cube
Finding the average
Scale drawings
Everything you need to prepare for an important exam!
K12 tests, GED math test, basic math tests, geometry tests, algebra tests.
Real Life Math Skills
Learn about investing money, budgeting your money, paying taxes, mortgage loans, and even the math involved in playing baseball.