by Sana
(Islamabad,Pakistan.)
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is
the age of the youngest child?
Let x be the age of the youngest child.
Let x + 3 be the age of the second child.
Let x + 6 be the age of the third child.
Let x + 9 be the age of the fourth child.
Let x + 12 be the age of the fifth child.
The sum of their ages is equal to 50 as shown below
x + x + 3 + x + 6 + x + 9 + x + 12 = 50
x + x + x + x + x + 3 + 6 + 9 + 12 = 50
5x + 30 = 50
Subtract 30 from both sides
5x + 30 - 30 = 50 - 30
5x = 20
Divide both sides by 5
5x/5 = 20/5
x = 4
The age of the youngest child is 4.
Jul 06, 18 12:29 PM
Learn how to solve two types of logarithmic equations
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.
Jul 06, 18 12:29 PM
Learn how to solve two types of logarithmic equations
Our Top Pages
Formula for percentage
Compatible numbers
Basic math test
Basic math formulas
Types of angles
Math problem solver
Algebra word problems
Surface area of a cube
Finding the average
Scale drawings
Everything you need to prepare for an important exam!
K-12 tests, GED math test, basic math tests, geometry tests, algebra tests.
Real Life Math Skills
Learn about investing money, budgeting your money, paying taxes, mortgage loans, and even the math involved in playing baseball.