by shen
(malaysia)
A factory has 800 workers. 40% of them are females. The management decides to
employ more female workers to cope with the increasing demands of the workload
such that the total number of females will increase to 60% of the total workforce.
How many new female workers must the factory employ?
Solution
How many female workers do they have now before hiring more?
Find 40% of 800
40% of 800 is equal to 0.40 × 800 = 320.
Now it is a percent of increase problem.
Percent of increase = (final amount  original amount) ÷ original amount
Percent of increase = 60%
Final amount = x
Original amount = 3200
60% = (x  320) ÷ 320
Simplify the right side. We do this by dividing x by 320 and 320 by 320.
We get the following:
0.60 = x/320  1
x/320  1 = 0.60
add 1 to both sides
x/320 = 1.60
Multiply both sides by 320
(x/320) × 320 = 320 × 1.60
x = 512
512  320 = 192.
They must hire 192 female workers
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