How to do synthetic division

This lesson will explain how to do synthetic division to quickly divide a polynomial by another.

Synthetic division is also called the method of detached coefficients. This is because the first step in synthetic division is to remove the coefficients from the polynomial that is being divided.

A couple of  synthetic division examples are shown below.

Divide x2 + 11x + 30 by x + 5

Step 1

Reverse the sign of the constant term in the divisor. For example, the constant term in the divisor is 5. Change it to -5. Remove the coefficients from the dividend and rewrite the division as shown below in blue.

                              ________________________                                       
                x + 5     |  x ²  +  11x  +  30

                       -5  |    1       11     30   

Step 2

Bring down the  first coefficient or 1. The 1 will begin the quotient. 

                        -5      |    1       11      30   
                         ________________________
                                       1

Step 3

Multiply the first coefficient by the new divisor and add the answer to the next coefficient or 11. We get 6. write down 6 in the same position as 11 and -5.

                       -5      |    1       11      30   
                                                -5
                             ________________________
                                      
1         6

Step 4

Keep multiplying and adding until the remainder is found. For example, multiply 6 by -5. We get -30. Add -30 to 30 to get 0 and 0 is the remainder. In fact, the last number on the right that you find after you add is the remainder whether it is 0 or not. 

                        -5      |    1       11       30   
                                                 -5       -30
                             ______________________
                                       
1         6         0

The quotient is x + 6


How to do synthetic division when the degree of the polynomial is 3

Divide x3 + 5x2 -2x - 24 by x - 2

Step 1

                              ________________________                                       
                x - 2     |  x ³   +  5x²   -   2x   -  24

                       2   |    1        5         -2       -24   

Step 2

                      2  |    1        5        -2       -24   
                        __________________________
                                1

Step 3

                     2  |    1        5        -2       -24
                                          2  
                         __________________________     
                               1         7

                    2  |    1        5        -2       -24 
                                        2        14
                         __________________________      
                              1        7        12

                    2  |    1        5        -2       -24 
                                        2        14       24
                         __________________________      
                              1        7        12         0

The quotient is  x² + 7x + 12







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