by Sahana
(Kolkata)
Arvind is eight year older than his sister. in three year, he will be twice as old as his sister. how old was they are now?
Solution
Let x be a Arvind's age.
Let x - 8 be his sister's age.
In 3 years, Arvind's age will be x + 3
In 3 years, the sister's age will be x - 8 + 3 = x - 5
In 3 years, Arvind is twice as old as his sister.
x + 3 = 2 × (x - 5)
x + 3 = 2x - 10
2x - 10 = x + 3
Subtract x from both sides.
2x - x - 10 = x - x + 3
2x - x - 10 = 3
Add 10 to both sides
2x - x - 10 + 10 = 3 + 10
2x - x = 3 + 10
x = 13
Arvind's age is 13
His sister's age is 13 - 8 = 5.
In 3 years, Arvind's will be 16 and the sister will be 8.
16 is twice as big as 8.
New math lessons
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Dec 01, 16 06:27 AM
1. Think of any positive whole number. No fractions, no decimals,no percents. 2. Double that number. 3. Add 10 to that result in step 2. 4. Divide