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Percent of increaseJust like the name suggests, the percent of increase is the amount of increase out of one hundred. Thus, the formula to use is : Amount of increase / Original amount I will illustrate what I just said with examples. example #1: Find the percent of increase from 4 to 6. Amount of increase is 6 − 4 = 2 Original amount is 4 2 / 4 = 0.50 multiply 0.50 by one hundred to get the answer as a percent. 0.50 × 100 = 50, so the answer is 50%. To check the answer, do the following: 4 × 50% = (4 × 50)/100 = 200/100 = 2 and 4 + 2 = 6 Notice that to convert 2 / 4 as a percent, we can multiply 4 by 25 and multiply 2 by 25 (2 × 25)/(4 × 25) = 50/100 or 50 per hundred or 50% When the denominator can divide 100, it may be easier to do it like that. example #2: Find the percent of increase from 5 to 10. Amount of increase is 10 − 5 = 5 Original amount is 5 5 / 5 = 1 multiply 1 by one hundred to get the answer as a percent 1 × 100 = 100, so the answer is 100%. To check the answer, do the following: 5 × 100% = (5 × 100)/100 = 500/100 = 5 and 5 + 5 = 10 Once again, we can convert 5 / 5 into percent by multiplying the numerator and the denominator by 25 (5 × 25)/(5 × 25) = 100/100 or 100 per hundred or 100% A tricky example? Find the percent of increase from -4 to 8. Amount of increase is 8 − -4 = 12 Original amount is -4 12 / -4 = -3 multiply -3 by one hundred to get the answer as a percent -3 × 100 = -300, so the answer is -300%. The reason I called this example tricky is because many poeple feel like the negative sign next to 300 does not really reflect an increase from -4 to 8 However, let's check the answer like we did for the two problems above! -4 × -300% = (-4 × -300)/100 = 1200/100 = 12 and -4 + 12 = 8 If you don't include the negative sign, you will get -1200/100 = -12 and -4 + -12 = -16 instead of 8 Need a Quick Answer to your Basic Mathematics Problems? Get an answer in 10 minutes or less from a math expert! Justanswer features top-notch math experts handpicked by personnel after they have taken and passed a rigourous math test and after their credentials have been verified by a third party
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