Revenue Function
All you need to find the revenue function is a strong knowledge of how to find the slope intercept form when a real life situation is given
Then, you will need to use the formula for the revenue (R = x × p)
x is the number of items sold and p is the price of one item
Real life example:
After some research, a company found out that if the price of a product is 50 dollars, the demand is 6000. However, if the price is 70 dollars, the demand is 5000.
Find the revenue function. Then calculate f(4249), f(4250), and f(4251). What is your observation?
Solution or modeling :
Notice that the demand depends on the price of the product. The higher the price, the less the demand.
If x is the demand or how many items are sold and p is the price, we can then say that x depends on p.
As a point, you can write (p, x)
Notice that the dependant variable is always put on the right in the ordered pair.
There are two ordered pair for the situation above. There are (50, 6000) and (70, 5000)
m =
x_{1}  x_{2}
/
p_{1}  p_{2}
m =
6000  5000
/
50  70
m = 50
x = 50p + b
To find b, use (70, 5000)
Here p = 70 and x = 5000
5000 = 50 × 70 + b
5000 = 3500 + b
5000 + 3500 = 3500 + 3500 + b
8500 = b
x = 50p + 8500
x = 50p + 8500 is the demand equation and it depends on the price
To find the
revenue function, use R = x × p
To find p, use x = 50p + 8500 to solve for p
x = 50p + 8500
x  8500 = 50p + 8500  8500
x  8500 = 50p
Divide both sides by 50
R = x × p
R = x × (
x  8500
/
50
)
R = x × (
x
/
50
+ 170 )
Instead of using R, you can use f(x) to denote that it is a function
f(x) =
x^{2}
/
50
+ 170x
f(4249) =
4249^{2}
/
50
+ 170 (4249)
f(4249) =
18054001
/
50
+ 722330
f(4249) = 361080.02 + 722330 = 361249.98
f(4250) =
4250^{2}
/
50
+ 170 (4250)
f(4250) =
18062500
/
50
+ 722500
f(4250) = 361250 + 722500 = 361250
f(4251) =
4251^{2}
/
50
+ 170 (4251)
f(4251) =
18071001
/
50
+ 722670
f(4251) = 361420.02 + 722670 = 361249.98
Notice that increasing the amount of items sold from 4250 to 4251 did not increase the revenue
This means that the maximum money you can make with this revenue function is 361250 and you are better off selling 4250 items to maximize your revenue

Oct 17, 17 05:34 PM
Factoring quadratic equations worksheetget some practice factoring quadratic equations
Read More
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.