Solve real world problems with a system of linear equations

by jhduHU
(COACIPC)

A burger place sells burgers (b) for $4, and fries (f) for $2. If bob bought six items for a total of $18, how many did he buy of each?


Solution

A system of linear equations can be used to solve this problem.

Let b be the number of burgers bob bought

Let f be the number of orders he placed for French fries

Then, we can come up with the following two equations

4b + 2f = 18 (equation 1)

b + f = 6 (equation 2)

Solve for b in equation 2. We can do this by subtracting f from both sides of the equation

b + f - f = 6 - f

b = 6 - f

Replace b with 6 - f in equation 1

4 (6 - f) + 2f = 18

4x6 - 4xf + 2f = 18

24 - 4f + 2f = 18

24 - 2f = 18

24 - 18 = 2f

6 = 2f

f = 3

Since b = 6 - f, b = 6 - 3 = 3

Therefore, Bob ordered 3 items each



Click here to post comments

Join in and write your own page! It's easy to do. How? Simply click here to return to System of linear equations.







Recent Articles

  1. Bessy and Bob algebra word problem

    Jul 28, 17 02:38 PM

    Bessy has 6 times as much money as Bob, but when each earn $6. Bessy will have 3 times as much money as Bob. How much does each have before and after

    Read More

New math lessons

Your email is safe with us. We will only use it to inform you about new math lessons.

            Follow me on Pinterest


Page copy protected against web site content infringement by Copyscape