A good way to start off with the proof of the area of a triangle is to use the area of a rectangle to quickly derive the area of a right triangle.

Start with a rectangle ABCD and let h be the height and b be the base as shown below:

However, if we draw a diagonal from one vertex, it will break the rectangle into two congruent or equal triangles

Although it does make sense, the proof is incomplete because triangle ABC is a right triangle or what we can also call a special triangle

How do we know the formula is going to work for any triangle, such as isosceles, equilateral, or scalene triangles?

If we can proove that the formula is the same for any arbitrary triangle such as a scalene triangle which has nothing particular about it, then it will work for special triangles such as isosceles, equilateral, or right triangle

So, let us start this time with a scalene triangle ABC which has nothing special about it

area of triangle ABC = (y × h)/2 + (x × h)/2

area of triangle ABC = (y × h + x × h)/2

area of triangle ABC = h ×(y + x)/2

Notice that y + x is the length of the base of triangle ABC.

Thus, it is ok to say that y + x = b

Therefore, area of triangle ABC = (h × b)/2

Proof of the area of a triangle has come to completion. Any questions? Contact me