by Angela
(Detroit, MI)
Divide me by 10 and 3 remains. A square number my first digit to be. My second digit is the product of 1 and 3. All together I'm greater than 50.
Solution
First of all, we need to clarify what we mean by first digit and second digit.
The number that we will look for has 2 digits and it has the following format.
xy
x is the first digit
y is the second digit
Then, we need to clarify what a square number is.
A square number is the number whose square root is an integer
For example, 16 is a square number since square root of 16 is 4 and 4 is an integer.
Now we are ready to look for the number.
One thing that is easy to find is the second digit.
The second digit is the product of 1 and 3.
The product of 1 and 3 is 1 × 3 = 3
The number has the following format so far x3
A square number my first digit to be.
If the first digit is a square number, the choices we have are only 4 and 9.
Since the number is bigger than 50, then the first digit has to be 9.
The number is therefore 93.
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Oct 24, 16 06:10 PM
Straightforward proof of the law of sines. Easy to follow and understand