A Geometry problem involving triangles
by Soumya Das
ACEF and ACDB are rectangles. BDEF is a square and the length of each side is 1 unit. If BG has a length of a, then what will be the length of AB?
First, show that triangle ABG and triangle AFE are similar.
Angle A is the same for triangle ABG and triangle AFE
Similarly, angle F is the same for triangle ABG and triangle AFE
Since triangle ABG and triangle AFE have two angles that have the same measure, the last angle for these two triangles must be the same.
Therefore, triangle ABG and triangle AFE are similar.
Since triangle ABG and triangle AFE are similar, we can use proportion to find ? or the length of AB.
AB/a = (AB + 1)/1
AB × 1 = a × AB + a × 1
AB = a(AB) + a
AB - a(AB) = a
AB(1-a) = a
AB(1-a)/(1-a) = a/1-a
AB = a/1-a
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Jul 03, 20 09:51 AM
factoring trinomials (ax^2 + bx + c ) when a is equal to 1 is the goal of this lesson.
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