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These cool math tricks help you solve basic math problems in your head, with speed and great accuracy. No calculator needed! Each trick comes with worked examples, a short explanation of why it works, and a problem to try yourself.
Even if you know your multiplication table, this trick comes in handy when you have a sudden brain freeze. It works for 9 × 1 through 9 × 10.
Hold up both hands, palms facing you. Starting with your left little finger, number your fingers from 1 to 10, as shown below.

Fold down your fifth finger.

There are 4 fingers to the left of the folded finger and 5 fingers to the right. So 9 × 5 = 45.
Fold down your sixth finger.

There are 5 fingers to the left of the folded finger and 4 fingers to the right. So 9 × 6 = 54.
Why it works: folding finger n leaves n − 1 fingers on the left and 10 − n on the right. And 9 × n is exactly (n − 1) tens plus (10 − n) ones. For n = 6: 5 tens + 4 ones = 54.
Fold down finger 7. There are 6 fingers on the left and 3 on the right, so 9 × 7 = 63.
On paper, most of us add from right to left, and that's fine. But to add two-digit numbers fast in your head, it's easier to work from left to right: add the tens first, then the ones.
Step 1: Rewrite 23 as 20 + 3.
Step 2: Add the tens: 56 + 20 = 76.
Step 3: Add the ones: 76 + 3 = 79.
Step 1: Rewrite 35 as 30 + 5.
Step 2: 64 + 30 = 94
Step 3: 94 + 5 = 99
Why it works: adding tens only changes the tens digit, which is easy to do in your head. Then you only have one small number left to add.
47 + 30 = 77, then 77 + 8 = 85.
Example 5: 65 × 10 = 650
Example 6: 14,778 × 1,000 = 14,778,000
Decimals: adding zeros doesn't work for decimals (3.5 × 10 is not 3.50). Instead, move the decimal point one place to the right for each zero: 3.5 × 10 = 35, and 3.5 × 100 = 350.
Why it works: multiplying by 10 makes every digit worth 10 times more, so each digit shifts one place to the left. The new zero fills the empty ones place.
Write two zeros at the end: 23,000.
This trick squares a two-digit number much faster than the usual multiplication. The goal is to change the two numbers being multiplied so that one of them ends in zero.

To square 14, subtract 4 from one 14 to get 10, and add 4 to the other to get 18. Multiply 10 × 18 = 180, then add 4² = 16. So 14² = 196.
Why do we add 4²? Multiply out 10 × 18:
10 × 18 = (14 − 4)(14 + 4)
= 14 × 14 + 14 × 4 − 4 × 14 − 4 × 4
= 14² − 4²
So 10 × 18 is 4² less than 14². Adding 4² back gives exactly 14²:
14² = 10 × 18 + 4²
17² = (17 − 7)(17 + 7) + 7²
= 10 × 24 + 49
= 240 + 49 = 289
Use c = 3: 20 × 26 + 3² = 520 + 9 = 529.
When you multiply 6 by 2, 4, 6 or 8, the answer follows a pattern:
Example 8: 6 × 8 → ones digit 8, tens digit 4 → 48
6 × 6 → ones digit 6, tens digit 3 → 36
Why it works: 6 × n = 5 × n + n. For an even n, 5 × n is a whole number of tens (n ÷ 2 tens), and the extra n gives the ones digit.
Ones digit 4, tens digit 2: 24.
Step 1: 18 × 10 = 180
Step 2: 180 − 18 = 162
Why it works: 9 is one less than 10.
18 × 9 = 18 × (10 − 1) = 18 × 10 − 18 = 180 − 18
We use it because multiplying by 10 is easy.
370 − 37 = 333.
Suppose you're subtracting 28 from 65. Vertical subtraction works, but when you need an answer fast, there's no time for borrowing and regrouping.
65 − 28: subtract 30 to get 35. You took away 2 too many, so add 2: 37.
461 − 300 = 161
161 + 3 = 164
Done in a snap, with no borrowing at all.
83 − 50 = 33, then 33 + 1 = 34.
41²: subtract 1 to get 40.
40² + 40 + 40 + 1 = 1,600 + 80 + 1 = 1,681
61² = 60² + 60 + 60 + 1 = 3,600 + 120 + 1 = 3,721
Why it works: (a + 1)² = a² + 2a + 1. When a ends in zero, a² and 2a are both easy to find in your head.
70² + 140 + 1 = 4,900 + 140 + 1 = 5,041.
Need to know whether something can be shared evenly between 2, 3, 4… or 10 people? Skip the long division and use the divisibility rules:
| By | A number is divisible if… |
|---|---|
| 2 | its last digit is even (0, 2, 4, 6 or 8) |
| 3 | the sum of its digits is divisible by 3 |
| 4 | its last two digits form a number divisible by 4 |
| 5 | its last digit is 0 or 5 |
| 6 | it is divisible by both 2 and 3 |
| 7 | doubling the last digit and subtracting it from the rest of the number gives a multiple of 7 |
| 8 | its last three digits form a number divisible by 8 |
| 9 | the sum of its digits is divisible by 9 |
| 10 | its last digit is 0 |
Can you share $4,557 evenly between you and your two sisters?
That's 3 people, so check divisibility by 3.
4 + 5 + 5 + 7 = 21, and 21 is divisible by 3.
So the answer is yes.
It's even, so it's divisible by 2. Its digits add up to 1 + 2 + 3 + 6 = 12, which is divisible by 3. Divisible by both 2 and 3 means yes (1,236 ÷ 6 = 206).
3 × 1,500 = 4,500, so take 4,500 first.
That leaves 4,557 − 4,500 = 57.
3 × 19 = 57
4,557 ÷ 3 = 1,500 + 19 = 1,519
So each person in Example 12 gets $1,519.
4 × 600 = 2,400, leaving 168. And 4 × 42 = 168. So 2,568 ÷ 4 = 600 + 42 = 642.
Each trick below has its own lesson with examples.
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