by Sana
(Islamabad,Pakistan.)
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Let x be the age of the youngest child.
Let x + 3 be the age of the second child.
Let x + 6 be the age of the third child.
Let x + 9 be the age of the fourth child.
Let x + 12 be the age of the fifth child.
The sum of their ages is equal to 50 as shown below
x + x + 3 + x + 6 + x + 9 + x + 12 = 50
x + x + x + x + x + 3 + 6 + 9 + 12 = 50
5x + 30 = 50
Subtract 30 from both sides
5x + 30 - 30 = 50 - 30
5x = 20
Divide both sides by 5
5x/5 = 20/5
x = 4
The age of the youngest child is 4.
Aug 22, 19 05:03 PM
How to test for symmetry - Graphs of relations can have two different types of symmetry.
Basic math formulas
Algebra word problems
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.
Recommended
Scientific Notation Quiz
Graphing Slope Quiz
Adding and Subtracting Matrices Quiz
Factoring Trinomials Quiz
Solving Absolute Value Equations Quiz
Order of Operations Quiz
Types of angles quiz
Aug 22, 19 05:03 PM
How to test for symmetry - Graphs of relations can have two different types of symmetry.