# Applications: Number problems and consecutive integers

Sum of 3 consecutive odd integers is -3, what are the integers?

Solution

A number is odd if it has the following format: 2n + 1

Let 2n + 1 be the first odd integer

Let 2n + 3 be the second odd integer

Let 2n + 5 be the third odd integer

Since the sum is equal to -3, we get the following equation:

2n + 1 + 2n + 3 + 2n + 5 = -3

2n + 2n + 2n + 1 + 3 + 5 = -3

6n + 9 = -3

6n + 9 - 9 = -3 - 9

6n + 0 = -12

6n = -12

Divide both sides by 6

6n / 6 = -12 / 6

n = -2

The first odd integer is 2n + 1 = 2 × -2 + 1 = -4 + 1 = -3

The second odd integer is 2n + 3 = 2 × -2 + 3 = -4 + 3 = -1

The third odd integer is 2n + 5 = 2 × -2 + 5 = -4 + 5 = 1

The 3 consecutive odd integers are -3, -1, and 1

Indeed -3 + -1 + 1 = -3 + 0 = -3

Algebra ebook

### Comments for Applications: Number problems and consecutive integers

Average Rating     Jan 31, 2017 Rating     Easier Way NEW by: Anonymous You get the correct answer, but you make it WAY more complicated than it needs to be. X=1st number y=2nd number= x+2 Z=3rd number= x+4 X + y + Z = -3 X + (x+2) + (x+4)= -3 3x + 6 = -3 3x = -9 X = -3 Y = (x+2) = -1 Z = (x+4) = 1

100 Tough Algebra Word Problems.

If you can solve these problems with no help, you must be a genius!