Calculate hotel saving

The cost of staying one night at a hotel in Amber City is forty-five dollars. The cost of staying one night at a hotel in Bear Lake is one-hundred forty-five dollars. Find the amount saved on a 4 night stay in Amber City instead of Bear Lake.

Solution #1

4 nights in Amber cost 45 × 4 = 180

4 nights in Bear Lake cost 145 × 4 = 580

The saving is 580 - 180 = 400

Solution # 2

Saving for one night in Amber is 145 - 45 = 100

So, saving for 4 nights is 100 × 4 = 400

Click here to post comments

Join in and write your own page! It's easy to do. How? Simply click here to return to Basic math word problem.

Recent Articles

  1. Quadratic Formula: Easy To Follow Steps

    Jan 26, 23 11:44 AM

    Quadratic formula
    Learn about the quadratic formula, the discriminant, important definitions related to the formula, and applications.

    Read More

  2. Area Formula - List of Important Formulas

    Jan 25, 23 05:54 AM

    Frequently used area formulas
    What is the area formula for a two-dimensional figure? Here is a list of the ones that you must know!

    Read More

Tough algebra word problems

100 Tough Algebra Word Problems.

If you can solve these problems with no help, you must be a genius!

Math quizzes


Math vocabulary quizzes