We show you in this lesson how to convert a quadratic function from the vertex form to the general form.
The vertex form is f(x) = a(x - h)^{2} + k and the general form is f(x) = ax^{2} + bx + c
Using f(x) = a(x - h)^{2} + k, you can just expand the function
f(x) = a(x - h)^{2} + k
f(x) = a(x - h)(x - h) + k
f(x) = a(x^{2} - hx - hx + h^{2}) + k
f(x) = a(x^{2} - 2hx + h^{2}) + k
f(x) = ax^{2} - 2ahx + ah^{2} + k
Method #1
You can then use f(x) = ax^{2} - 2ahx + ah^{2} + k as a sort of "formula"
Comparing the expression above with f(x) = ax^{2} + bx + c, we notice the following:
a = a
b = - 2ah
c = ah^{2} + k
Suppose y = 2(x + 3)^{2} + 1
Rewrite in vertex form: y = 2(x - -3)^{2} + 1
a = 2
b = - 2ah = -2(2)(-3) = (-4)(-3) =12
c = ah^{2} + k = 2(-3)^{2} + 1 = 2(9) + 1 = 19
f(x) = ax^{2} + bx + c = 2x^{2} + 12x + 19
Method #2
Instead of using the "formula" or f(x) = ax^{2} - 2ahx + ah^{2} + k, you can just expand y = 2(x + 3)^{2} + 1.
y = 2(x + 3)^{2} + 1
y = 2(x + 3)(x + 3) + 1
y = 2(x^{2} + 3x + 3x + 9) + 1
y = 2(x^{2} + 6x + 9) + 1
y = 2x^{2} + 12x + 18 + 1
y = 2x^{2} + 12x + 19
Jan 12, 22 07:48 AM
This lesson will show you how to construct parallel lines with easy to follow steps