Math problem about age

by Sahana
(Kolkata)

Arvind is eight year older than his sister. in three year, he will be twice as old as his sister. how old was they are now?

Solution

Let x be a Arvind's age.

Let x - 8 be his sister's age.

In 3 years, Arvind's age will be x + 3

In 3 years, the sister's age will be x - 8 + 3 = x - 5

In 3 years, Arvind is twice as old as his sister.

x + 3 = 2 × (x - 5)

x + 3 = 2x - 10

2x - 10 = x + 3

Subtract x from both sides.

2x - x - 10 = x - x + 3

2x - x - 10 = 3

Add 10 to both sides

2x - x - 10 + 10 = 3 + 10

2x - x = 3 + 10

x = 13


Arvind's age is 13

His sister's age is 13 - 8 = 5.

In 3 years, Arvind's will be 16 and the sister will be 8.

16 is twice as big as 8.


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Jun 18, 2018
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Arvin and her Sister NEW
by: Anonymous

Arvin is 8 years older than her sister
why will you reduce the age of her sister
it should be plus 8 to be equal to Arvin's Age
the equation should be
Arvin=Sister+8

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