by Angela

(Detroit, MI)

Divide me by 10 and 3 remains. A square number my first digit to be. My second digit is the product of 1 and 3. All together I'm greater than 50.**Solution**

First of all, we need to clarify what we mean by **first digit** and **second digit**.

The number that we will look for has 2 digits and it has the following format:

xy

x is the first digit

y is the second digit

Then, we need to clarify what a **square number** is.

A square number is the number whose square root is an integer.

For example, 16 is a square number since square root of 16 is 4 and 4 is an integer.

Now we are ready to look for the number.

One thing that is easy to find is the second digit.

The second digit is the product of 1 and 3.

The product of 1 and 3 is 1 × 3 = 3

The number has the following format so far x3

A square number my first digit to be.

If the first digit is a square number, the choices we have are only 4 and 9.

Since the number is bigger than 50, then the first digit has to be 9.

The number is therefore 93.