Solve by completing the square
Solve by completing the square could take a little bit more time to do than solving by factoring. However, the steps are straightforward.
Before showing examples, you need to understand what a perfect square trinomial is
Binomial × same Binomial = Perfect square trinomial
(x + 4) × (x + 4) = x
^{2} + 4x + 4x + 16 = x
^{2} + 8x + 16
(x + a) × (x + a) = x
^{2} + ax + ax + a
^{2} = x
^{2} + 2ax + a
^{2}
Important observation:
What is the relationship between the coefficient of the second term and the last term?
For x
^{2} + 8x + 16, coefficient of the second term is 8 and the last term is 16
(8/2)
^{2} = 4
^{2} = 16
For, x
^{2} + 2ax + a
^{2}, the coefficient of the second term is 2a and the last term is a
^{2}
(2a/2)
^{2} = a
^{2}
So, what is the relationship?
The last term is obtained by dividing the coefficient of the second term by 2 and squaring the result
Now, let's say you have x
^{2} + 20x and you want to find the last term to make the whole thing a perfect square trinomial
Just do (20/2)
^{2} = 10
^{2}. The perfect square trinomial is x
^{2} + 20x + 10
^{2}= (x + 10) × (x + 10)
Example #1:
Solve by completing the square x
^{2} + 6x + 8 = 0
x
^{2} + 6x + 8 = 0
Subtract 8 from both sides of the equation.
x
^{2} + 6x + 8  8 = 0  8
x
^{2} + 6x =  8
To complete the square, always do the following 24 hours a day 365 days a year. It is never going to change when you solve by completing the square!
You are basically looking for a term to add to x
^{2} + 6x that will make it a perfect square trinomial.
To this end, get the coefficient of the second term, divide it by 2 and raise it to the second power.
The second term is 6x and the coefficient is 6.
6/2 = 3 and after squaring 3, we get 3
^{2}
x
^{2} + 6x =  8
Add 3
^{2} to both sides of the equation above
x
^{2} + 6x + 3
^{2} =  8 + 3
^{2}
x
^{2} + 6x + 3
^{2} =  8 + 3
^{2}
(x + 3)
^{2} = 8 + 9
(x + 3)
^{2} = 1
Take the square root of both sides
√((x + 3)
^{2}) = √(1)
x + 3 = ±1
When x + 3 = 1, x = 2
When x + 3 = 1, x = 4
Example #2:
Solve by completing the square x
^{2} + 6x + 8 = 0 instead of x
^{2} + 6x + 8 = 0
The second term this time is 6x and the coefficient is 6.
6/2 = 3 and after squaring 3, we get (3)
^{2} = 9
x
^{2} + 6x =  8
Add (3)
^{2} to both sides of the equation above
x
^{2} + 6x + (3)
^{2} =  8 + (3)
^{2}
(x + 3)
^{2} = 8 + 9
(x + 3)
^{2} = 1
Take the square root of both sides
√((x + 3)
^{2}) = √(1)
x + 3 = ±1
When x + 3 = 1, x = 4
When x + 3 = 1, x = 2
Example #3:
Solve by completing the square 3x
^{2} + 8x + 3 = 0
3x
^{2} + 8x + 3 = 0
Divide everything by 3. Always do that when the coefficient of the first term is not 1
(3/3)x
^{2}+ (8/3)x + 3/3 = 0/3
x
^{2}+ (8/3)x + 1 = 0
Add 1 to both sides of the equation.
x
^{2} + (8/3)x + 1 + 1 = 0 + 1
x
^{2} + (8/3)x = 1
The second term is (8/3)x and the coefficient is 8/3.
8/3 ÷ 2 = 8/3 × 1/2 = 8/6 and after squaring 8/6, we get (8/6)
^{2}
x
^{2} + (8/3)x = 1
Add (8/6)
^{2} to both sides of the equation above
x
^{2} + (8/3)x + (8/6)
^{2} = 1 + (8/6)
^{2}
(x + 8/6)
^{2} = 1 + 64/36
(x + 8/6)
^{2} = 36/36 + 64/36 = (36 + 64)/36 = 100/36
Take the square root of both sides
√((x + 8/6)
^{2}) = √(100/36)
x + 8/6 = ±10/6
x + 8/6 = 10/6
x = 10/6  8/6 = 2/6 = 1/3
x + 8/6 =  10/6
x = 10/6  8/6 = 18/6 = 3
To solve by completing the square can become quickly hard as shown in example #3

Mar 13, 19 11:50 AM
Learn how to derive the equation of an ellipse when the center of the ellipse is at the origin.
Read More
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.