Surface area of a sphere
To derive the formula of the surface area of a sphere, we imagine a sphere with many pyramids inside of it until the base of all the pyramids cover the entire surface area of the sphere. In the figure below, only one of such pyramid is shown.
Then, do a ratio of the
area of the pyramid to the
volume of the pyramid.
The area of the pyramid is A
The volume of the pyramid is V = (1/3) × A × r = (A × r) / 3
So, the ratio of area to volume is the following:
A
pyramid / V
pyramid = A ÷ (A × r) / 3 = (3 × A) / (A × r ) = 3 / r
Now pay careful attention to the following important stuff!
Observation # 1:
For a large number of pyramids, let's say that n is such large number, the ratio of the
surface area of the sphere to the
volume of the sphere is the same as 3 / r
Why is that? That cannot be true! Well, here is the reason:
For n pyramids, the total area is n × A
Also for n pyramids, the total volume is n × V
Therefore, ratio of total area to total volume is n × A / n × V = A / V.
Therefore, A
sphere / V
sphere is also equal to 3 / r
Observation # 2:
Furthermore, n × A
pyramid = A
sphere (The total area of the bases of all pyramids or n pyramids is approximately equal to the surface area of the sphere)
n × V
pyramid = V
sphere ( The total volume of all pyramids or n pyramids is approximately equal to the volume of the sphere.
Putting observation # 1 and # 2 together, we get:
Asphere / Vsphere = n(Apyramid) / n(Vpyramid) = Apyramid / Vpyramid = 3 / r
Therefore,
Therefore, the total surface area of a sphere, call it SA is:
SA = 4 × pi × r
2
A couple of examples showing how to find the surface area of a sphere.
Example #1:
Find the surface area of a sphere with a radius of 6 cm
SA = 4 × pi × r
2
SA = 4 × 3.14 × 6
2
SA = 12.56 × 36
SA = 452.16
Surface area = 452.16 cm
2
Example #2:
Find the surface area of a sphere with a radius of 2 cm
SA = 4 × pi × r
2
SA = 4 × 3.14 × 2
2
SA = 12.56 × 4
SA = 50.24
Surface area = 50.24 cm
2
-
Nov 18, 20 01:20 PM
Top-notch introduction to physics. One stop resource to a deep understanding of important concepts in physics
Read More
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.