The segment addition postulate states the following for 3 points that are collinear.

 Consider the segment on the right. If 3 points A, B, and C are collinear and B is between A and C, then

AB + BC = AC

## Using the segment addition postulate Suppose AC =  48, find the value of x. Then, find AB and BC

AB + BC = AC

( 2x - 4 ) +( 3x + 2 ) = 48

2x + 3x - 4 + 2 = 48

5x - 4 + 2 = 48

Add 4 to both sides of the equation

5x - 4 + 4 + 2 = 48 + 4

5x + 2 = 52

Subtract 2 from both sides

5x + 2 - 2 = 52 - 2

5x = 50

Divide both sides by 5

5x / 5 = 50 / 5

x = 10

AB = 2x - 4

AB = 2 × 10 - 4

AB = 20 - 4 = 16

BC = 3x + 2

BC = 3 × 10 + 2

BC = 30 + 2 = 32

## Segment addition postulate and the midpoint

Suppose XA = 3x and AY =  4x - 6. If A is the midpoint of XY, what is the length of XY?

3x                       4x - 6
_________________________________
X                         A                         Y

If A is the midpoint, XA = AY.

3x = 4x - 6

Subtract 3x from both sides

3x - 3x = 4x - 3x - 6

0  = x - 6

Add 6 to both sides of the equation

0 + 6 = x - 6 + 6

6 = x

XA = AY = 3 × 6 = 16

XY = XA + AY = 16 + 16 = 32

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