by jhduHU
(COACIPC)
A burger place sells burgers (b) for $4, and fries (f) for $2. If bob bought six items for a total of $18, how many did he buy of each?
Solution
A system of linear equations can be used to solve this problem.
Let b be the number of burgers bob bought
Let f be the number of orders he placed for French fries
Then, we can come up with the following two equations
4b + 2f = 18 (equation 1)
b + f = 6 (equation 2)
Solve for b in equation 2. We can do this by subtracting f from both sides of the equation
b + f - f = 6 - f
b = 6 - f
Replace b with 6 - f in equation 1
4 (6 - f) + 2f = 18
4x6 - 4xf + 2f = 18
24 - 4f + 2f = 18
24 - 2f = 18
24 - 18 = 2f
6 = 2f
f = 3
Since b = 6 - f, b = 6 - 3 = 3
Therefore, Bob ordered 3 items each
Sep 18, 19 01:16 PM
Factoring using the box method. Common pitfalls to avoid when using this method.
Basic math formulas
Algebra word problems
New math lessons
Your email is safe with us. We will only use it to inform you about new math lessons.
Recommended
Scientific Notation Quiz
Graphing Slope Quiz
Adding and Subtracting Matrices Quiz
Factoring Trinomials Quiz
Solving Absolute Value Equations Quiz
Order of Operations Quiz
Types of angles quiz
Sep 18, 19 01:16 PM
Factoring using the box method. Common pitfalls to avoid when using this method.