The perimeter of a rectangle is 138 inches. The length exceeds the width by 65 inches. Find the length and width.
Solution
P = 2l + 2w
l = w + 65
Substitute 138 for P and w + 65 for l
138 = 2( w + 65) + 2w
138 = 2w + 130 + 2w
138 = 4w + 130
138  130 = 4w + 130  130
8 = 4w
8/4 = (4/4)w
2 = w
l = 2 + 65 = 67
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