C_{A}
D_{A}

=
C_{B}
D_{B}

4 × C_{B}
D_{A}

=
C_{B}
7

If
2
5

=
8
20
then, 2 × 20 = 5 × 8

If
4 × C_{B}
D_{A}

=
C_{B}
7
then, 4 × C_{B} × 7 = D_{A} × C_{B}

C_{A}
D_{A}

=
C_{B}
D_{B}

4 × C_{B}
D_{A}

=
C_{B}
7

If
2
5

=
8
20
then, 2 × 20 = 5 × 8

If
4 × C_{B}
D_{A}

=
C_{B}
7

Mar 19, 18 05:53 PM
Triangle midsegment theorem proof using coordinate geometry and algebra
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Mar 19, 18 05:53 PM
Triangle midsegment theorem proof using coordinate geometry and algebra
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