2
5

and
3
6

2
6

,
1
6

and
5
6
all have a common denominator

Let us compare
2
3

and
3
4

Put 8 beneath
2
3

and 9 beneath
3
4

2
3

3
4

8

9

Since 8 is smaller than 9, then
2
3

<
3
4

Let us compare
5
6

and
6
8

Put 40 beneath
5
6

and 36 beneath
6
8

5
6

6
8

40

36

Since 40 is bigger than 36, then
5
6

>
6
8

Let us compare again
5
6

and
6
8

5
6

becomes
40
48

6
8

becomes
36
48

Since 40 is bigger than 36, then
40
48

>
36
48

Therefore,
5
6

>
6
8

6
10

>
5
10

Therefore,
2
10

>
2
15

2
5

and
3
6

2
6

,
1
6

and
5
6
all have a common denominator

Let us compare
2
3

and
3
4

Put 8 beneath
2
3

and 9 beneath
3
4

2
3

3
4

8

9

Since 8 is smaller than 9, then
2
3

<
3
4

Let us compare
5
6

and
6
8

Put 40 beneath
5
6

and 36 beneath
6
8

5
6

6
8

40

36

Since 40 is bigger than 36, then
5
6

>
6
8

Let us compare again
5
6

and
6
8

5
6

becomes
40
48

6
8

becomes
36
48

Since 40 is bigger than 36, then
40
48

>
36
48

Therefore,
5
6

>
6
8

6
10

>
5
10

Therefore,
2
10

>
2
15

Jul 06, 18 12:29 PM
Learn how to solve two types of logarithmic equations
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Jul 06, 18 12:29 PM
Learn how to solve two types of logarithmic equations
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